tag:blogger.com,1999:blog-5964889903484807623.post474214091349910984..comments2023-12-18T04:44:25.358-08:00Comments on Questions?: Did I Get It?David Coxhttp://www.blogger.com/profile/06277427735527075341noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-5964889903484807623.post-57182371534992888732022-12-06T13:41:33.897-08:002022-12-06T13:41:33.897-08:00re: last comment 8.Nov.22. If you set the two for...re: last comment 8.Nov.22. If you set the two formulas for n equal to each other (assume truth of both, try to verify if accurate), you get<br />m(m-k)/k + m = (m^2 - k^2)/k + k. Multiply by k on both sides and distribute, you get m^2 - km + km = m^2 - k^2 + k^2. This simplifies to 0 = 0, so they are equivalent equations. I also don't exactly know how the original formula came to be, but it doesn't contradict yours.Anonymoushttps://www.blogger.com/profile/07630717140057796743noreply@blogger.comtag:blogger.com,1999:blog-5964889903484807623.post-90977362796563912062022-11-08T23:13:46.408-08:002022-11-08T23:13:46.408-08:00I know this post is 10 years old, but I believe th...I know this post is 10 years old, but I believe the formula for N is incorrect. Shouldn't it be n=[(m^2 - k^2)/k]+k? I substituted k+m as the x and n as the y along with (m-k)/k as the slope into y=mx+b and simplified. I'm not certain how you achieved your formula for n. Great problem though that I'm presenting to my advanced-level 8th graders!Anonymoushttps://www.blogger.com/profile/09400656022684753437noreply@blogger.comtag:blogger.com,1999:blog-5964889903484807623.post-62569153926560901952012-06-13T15:58:25.042-07:002012-06-13T15:58:25.042-07:00Awesome question! Interesting comment above. I thi...Awesome question! Interesting comment above. I think the "openness" of the question would depend on the ability of the students. Personally, I would give this question to a year 9 or year 10 group and would keep it the way it is. The co-ordinates possibly act as a clue as to how a student might go about solving this. Depending on the ability, I would think about taking the co-ordinates out.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5964889903484807623.post-25929908597859757972012-05-23T10:50:00.247-07:002012-05-23T10:50:00.247-07:00I am stealing that question. I don't think I ...I am stealing that question. I don't think I will give the (0,4) coordinate and simply ask what they can tell me about the three squares.nonehttps://www.blogger.com/profile/04110704335563806513noreply@blogger.com