__Friday August 12, 2011__Kate poses a great problem.

__Thursday, November 17, 2011__Dan asks a great question.

To which I responded something like, "yeah, prolly, but it'd take a bunch of brute force."

__Saturday, November 19, 2011__I forward it to the GeoGebra Forum.

__Sunday, November 20, 2011__
Raymond responds.

This flow of information absolutely amazes me. I mean, I loved the question after Kate posted it. In fact, I immediately created an applet and had used the problem with my advanced class early in the first quarter. They struggled a bit with it, but then when Dan asked about highlighting the squares and doing some of the counting, things changed.

I consider myself to be a little better than average when using GeoGebra, but Raymond is a freaking Jedi. Take a look at his stuff. He takes an applet that I thought would require a number of tedious steps and bangs it out using 6 steps--and within 24 hours. That's ridiculous.

The applet is here.

## 2 comments:

Huh -- I don't know if anyone has pointed this out already, but it appears that (number of boxes) / (length of diagonal) is always between 1/sqrt(2) and sqrt(2). The lower limit is easy to understand, but the upper limit is intriguing (if it's correct).

And I can sit in bed on a Sunday morning and take it all in on my iPad, even playing with the applet. Brilliant!

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